Monday, 24 December 2012
Checking if a number is Armstrong number:
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The program for Checking if a number is Armstrong number:
//Armstrong Number:: abc==a3+b3+c3
#include<stdio.h>
#include<conio.h>
void main()
{
int input,s=0,a,b;
clrscr();
printf("Enter the number you want to check:");
scanf("%d",&input);
a=input;
while(a!=0)
{
b=a%10;
a=a/10;
s=s+(b*b*b);
}
if(s==input)
{
printf("Yes! %d Is a Armstrong Number.",input);
}
else
{
printf("No! Its not a Armstrong number");
}
getch();
}
the output is like:
This post was written by: Franklin Manuel
Franklin Manuel is a professional blogger, web designer and front end web developer. Follow him on Twitter
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2 Responses to “Checking if a number is Armstrong number:”
30 May 2013 at 00:20
what a program... excelent work thanks bro...
3 April 2022 at 19:12
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